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Free
03-03-2003, 06:47 AM
A vy mojete dokazat chto 0=2?
Mr Potatokiller
03-03-2003, 01:18 PM
Äîêàçàòü åòî íåâîçìîæíî!
kkk[log_off]
03-04-2003, 03:32 PM
hehe..Delta dokajet pol'zuyas' teoriyami Einsteina(special meshial relativiti pelativiti) :P..vot uvidesh:)
Free
03-05-2003, 05:26 AM
nu a mojet mojete dokazat -2=2
Mr Potatokiller
03-05-2003, 09:06 AM
1) 2 = 2

2) 2*(-1) = 2

3) -2=2 !! Evrikka
trigger-happy
03-05-2003, 09:43 AM
Potato-aka,

2*(-1) =/ 2
Free
03-06-2003, 07:17 AM
-2=2
(-2)*2=(2)*2
4=4 Vot teper evrika
No Mr potato toje ochen yaqinlashti
trigger-happy
03-06-2003, 07:22 AM
Becky, (-2)*2 = -2. But you gave me an idea.
Instead of *, how about ^?
(-2)^2=(2)^2
Now it all fits, and -2=2
Now to disprove it,
(-2)^2=(-2)*(-2)
(2)^2=2*2
Then, -2=/2
Mr Potatokiller
03-06-2003, 07:50 AM
Becky, (-2)*2 = -2. But you gave me an idea.
Instead of *, how about ^?
(-2)^2=(2)^2
Now it all fits, and -2=2
Now to disprove it,
(-2)^2=(-2)*(-2)
(2)^2=2*2
Then, -2=/2

Ooopsy daisy..., never thought of it, but it is still wrong.
square root of 4 gives two different answers, -2 and 2
as you know y=x^2 is not a one to one function and fails the horizontal test. Which means, according to your theory, "a=-a" Uahahahahah!
trigger-happy
03-06-2003, 07:56 AM
Mr Potatokiller,
The question itself was a trick question: it is impossible to prove 2=-2, because it is not so. My solution was a trick solution and thus will fail any test. :P
Mr Potatokiller
03-06-2003, 11:41 PM
A vy mojete dokazat chto 0=2? this type of questions are not a challenge, for these statements do not hold true.
BUT, if anyone can prove that 1+1=2, then you may as well go and claim your Phd for Mathematics. My Calculus teacher once showed me this 302 page book that was only written about the proof of a+a=2a. 302 pages!!! Aghhhh!
I can imagine what the author's face would look like if the commity of mathematicians rejected that proof and told him that he just wasted 11 years of his life writing random digits that were no use. That would hurt, I bet.... :? , cos I experienced something very simmilar yet less painfull.
Free
03-07-2003, 09:26 AM
Sorry mates,
there was a little mistake in my solution.
Here is true one:
V matematike prakticheski eto ne vajno v kakuyu ty v storonu hochesh poyti.Glavnoe dokazat to chto nujno.Vot naprimer est odin variant payti s 4=4 .
4=4
(-2)^2=(2)^2
2=2
noodles
03-07-2003, 04:53 PM
2x2=5, prove it ;)
Free
03-08-2003, 10:06 AM
2x2=5, prove it

Avazbek its impossible to prove it ,cause 2x2=3.
noodles
03-08-2003, 12:03 PM
Becky,
Avazbek its impossible to prove it ,cause 2x2=3.
aight, no objection, then try to prove your own result :)
Free
03-08-2003, 12:15 PM
Avaz videsh tu X mejdu dvoykami vot etot X raven na 0,75.
noodles
03-08-2003, 12:27 PM
Don't know according to what theory you solved, would you clarify?:)
Archy
03-08-2003, 12:35 PM
à^2-a^2=(a-a)^2
(a+a)(a-a)=(a-a)(a-a)
à+à=à-à
a- any number
Mr Potatokiller
03-08-2003, 01:31 PM
à^2-a^2=(a-a)^2
(a+a)(a-a)=(a-a)(a-a)
à+à=à-à
a- any number

sure! (a-a)^2 = a^2 - 2aa + a^2 = 0

Moreover, (a-a)/(a-a) = indeterminable form
Free
03-09-2003, 04:49 AM
A_______________________________B

Esli AB=1 ,to gde budet nahoditsa 1/3 ?
LunatiK
03-09-2003, 10:44 AM
Mejdu A i B. :D :D

Jiddiyroq oladiga bolsak,
LunatiK
03-09-2003, 10:46 AM
Oops, my attachment didn't appear.
I cannot attach a file, how can I do this?
Free
03-10-2003, 01:19 AM
Mejdu A i B.

Jiddiyroq oladiga bolsak,

NoName, da mejdu A i B.
Gauss
03-13-2003, 03:53 PM
A vy mojete dokazat chto 0=2?

Look

0 = 2-2 yani 0x(1-1) = 2-2

yani 0x(1-1) = 2(1-1)
agar tenglamani ikki tomonini (1-1) ga bo'lib yuborsak 0 = 2

ha haha evrika
LunatiK
03-13-2003, 06:32 PM
A vy mojete dokazat chto 0=2?

Assume a, b are natural numbers and a > b . So there is such a c, (c is also a natural number) that a = b + c. Multiply both side by (a – b).

a*(a – b) = (b + c)*(a – b)
a^2 – ab = ab – b^2 + ac – bc
a^2 – ab – ac = ab – b^2 – bc
a (a – b – c) = b (a – b – c)
a = b

As a > b , let’s assume a = 2 and b = 0, so 2 = 0
LunatiK
03-13-2003, 07:22 PM
A_______________________________B

Esli AB=1 ,to gde budet nahoditsa 1/3 ?

Look at the attachment:
LunatiK
03-13-2003, 08:13 PM
A_______________________________B

Esli AB=1 ,to gde budet nahoditsa 1/3 ?

Look at the attachment:
03-14-2003, 07:24 AM
GUASS


OFARIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIN, eeeeeeeeeeeeee qoyilman super man!!!! :D
Free
03-14-2003, 08:10 AM
wooow 2 kun kirmaganda bunchalik matematiklar kelip kolishipti ku.NoName, bu sizning yechimingiz mi yoki boshkasiniki mi? anyway juda zor yechim.
i eshyoGauss: a4bb07fa, NoName, Archy, Mr Potatokiller: 2f3f8cca, vam nado dat Nobel Prize ,but unfortunatly matematikam nodebl ne dadut...


masalalar hali davom kiladi...
on duty
03-15-2003, 07:05 PM
a=bni isboti haqida:

a (a – b – c) = b (a – b – c) bunda a-b-c=0 (a=b+c)

shuning uchun 0=0

hehe, buyam o'hshamadi
Free
03-16-2003, 06:16 AM
on duty, ty prav no zadacha sostait v tom chtoby dokazat eto.po etomu lyudey ne interesuet chto a-b-c=0,
glavnoye dokazat i vsyo.
I_am_bandidos
04-15-2003, 02:45 PM
YO yO people, what's up?
Nelzya dokazat chto 0=2 ili 2*2=5 ili togo podobiye zadniya. No mojno poigrat odnu idiotskuyu igru tipa:

Vopros: dokaji a=b a i b lyubiye chisla daje manfiy.

Otvet (dolboyob5iy, no igra):

1. 2[a -(a+b/2)]=2[b-(a+b/2)] subtracting (a+b/2) from both sides and multiplying by 2 both sides.
1(result) (a-b)=(b-a)
2. (a-b)<square>=(b-a)<square> squaring both sides
3. a<square>-2ab+b<square>=b<square>-2ab+a<square>

Man, they are fu#king equal!!!
Lunatik.
04-15-2003, 08:04 PM
Yo I_am_bandidos,

Where did you get [a-(a+b/2)]=[b-(a+b/2)].
Man, they are not fu*king equal !!!
Think about it.
I_am_bandidos
04-16-2003, 11:21 AM
Smotri ya skazal pust a=b, i hochu chtob ya prishol k pravilnomu primeru (kak ya uje pokozal). Esli ti poymyosh, eta vesh tipa:

A:mulohaza B:mulohaza

=> (A<=>B) <=> (B<=>A) (which is only true for some problems, but not for this one)

Nu vot, ikala tarafdan (a+b/2) ayirib, 2 ga kopaytirdim :-).
Tushumayotgan_matematik
04-17-2003, 08:19 AM
I_am_bandidos,



Vopros: dokaji a=b a i b lyubiye chisla daje manfiy.





Smotri ya skazal pust a=b,



Bandidos, yuqorida a=b ekanligini isbotlamoqchi bo'lgansan, pastda esa a=b deb qabul qilaylik degansan. Agar a=b deb qabul qilgan bo'lsak, yana a=b ekanligini isbotlashning nima keragi bor ???
pppp
04-17-2003, 10:00 AM
I_am_bandidos,



Vopros: dokaji a=b a i b lyubiye chisla daje manfiy.





Smotri ya skazal pust a=b,



Bandidos, yuqorida a=b ekanligini isbotlamoqchi bo'lgansan, pastda esa a=b deb qabul qilaylik degansan. Agar a=b deb qabul qilgan bo'lsak, yana a=b ekanligini isbotlashning nima keragi bor ???


Ha-Ha-Ha...... Rostanham, a=b deb berilish berilgan bolsa, uni ispotini nima keragi bor? :P
I_am_bandidos
04-17-2003, 05:04 PM
Tushunmayotgan matematik va pppp odamlar, rebyata, gap shu erdada. Mana misol uchun.

Savol: 2x+5=13 , bo'lsa x=4 ekanligini ispotlang

Echim:

A:mulohaza B:mulohaza
=> (A<=>B) <=> (B<=>A) (o'zi faqat togriday eshitiladi, ammo -togri)

dan foydalanib, x=4 deylik shunda
2x=8 => 2x+5=13 bo'ladi. Teskarisidan bo'ldida

Misol uchun: 2=0 isbotlaylik.
2=0
2-1=0-1 ikala tarafdan 1 ni ayirdik
1=-1
(1)<square>=(-1)<square> ikala tarafni 2-darajaga ko'tardik.
shunda 1=1 bo'lib qoladi. Does it make sense now?
Terminator
05-31-2003, 01:12 PM
Sanchib quydinda banditos :D aylantirib aylantirib tenglashtirib quydinu. 2=0 ni isbotlamoqchimisan, 1=1 ni nima qilasan