Korotko i yasno.

[I_am_bandidos]

Davay g(x)=x*x

Esli [g(a)/b+c]+[g(b)/c+a]+[g(c)/a+b]=1 togda naydite

(a/b+c)+(b/c+a)+(c/a+b)=?

Tak udachi, kto reshit tamu dengi budut. :D

[I_am_bandidos]

Yeah baby! C'mon.

[Ppppp]

I would be interested in finding out the answer for this particular question of yours. Please do post the answer clear and fine.

Cheers,

PPPP

[I_am_bandidos]

Pri pisaniya voprosa ya dopustil odnu oshibochku, no eto oshibichka nemenyaet trudnost etoy zadachi.

Vopros doljen bit takim:
Esli [g(a)/b+c]+[g(b)/c+a]+[g(c)/a+b]=0

to naydite (a/b+c)+(b/c+a)+(c/a+b)=?

Otvet:

[g(a)/b+c]+[g(b)/c+a]+[g(c)/a+b]=0 add a+b+c to both sides

{g(a)/b+c]+a}+{(b)/c+a]+b}+{[g(c)/a+b]+c}=a+b+c

{a(a+b+c)/b+c}+{b(a+b+c)/c+a}+{c(a+b+c/a+b}=a+b+c teper obe storon sokratite na (a+b+c) togda

(a/b+c)+(b/c+a)+(c/a+b)=1

Is not it beautiful?

Mr Bandito, you seem to have a strong foundation in mathematics. Maybe, some day you will find the formula of the series of the stock market index values, that has yet not been claimed by anyone.

By the way, what course are studying?

Pri pisaniya voprosa ya dopustil odnu oshibochku, no eto oshibichka nemenyaet trudnost etoy zadachi.

Vopros doljen bit takim:
Esli [g(a)/b+c]+[g(b)/c+a]+[g(c)/a+b]=0

to naydite (a/b+c)+(b/c+a)+(c/a+b)=?

Otvet:

[g(a)/b+c]+[g(b)/c+a]+[g(c)/a+b]=0 add a+b+c to both sides

{g(a)/b+c]+a}+{(b)/c+a]+b}+{[g(c)/a+b]+c}=a+b+c

{a(a+b+c)/b+c}+{b(a+b+c)/c+a}+{c(a+b+c/a+b}=a+b+c teper obe storon sokratite na (a+b+c) togda

(a/b+c)+(b/c+a)+(c/a+b)=1

Is not it beautiful?

Wait a minute, I thought you stated that g(x)=x^2 which makes g(a)=a^2 g(b)=b^2 and g(c)=c^2, right?

[I_am_bandidos]

Yeah, man about g(x) stuff u r right. I know all math stuff, the problem that I discussed about was one of easy ones. I don't really study what teachers teach in universites, I study math olimpiads. Like go to www.kalva.demon.co.uk and u will find out a lot of interesting problems like that.