View Full Version : PLEASE BAN USER:cd3ce22d- He's been cursing/flooding/etc
RED ALERT!
05-28-2003, 11:18 AM
Moderators please ban the AntiChrist (User:cd3ce22d). He's been making too many personal lewd etc remarks, and flooding all over the place.
RED ALERT!
05-28-2003, 11:24 AM
http://www.forum.uz/viewtopic.php?t=13215
http://www.forum.uz/viewtopic.php?t=9298
http://www.forum.uz/viewtopic.php?t=13176
http://www.forum.uz/viewtopic.php?t=13181
http://www.forum.uz/viewtopic.php?t=13153&start=45
http://www.forum.uz/viewtopic.php?t=13172
http://www.forum.uz/viewtopic.php?t=13153&start=45
and four more posts in other sections. All posted within 15 minutes
MegaZ
05-28-2003, 09:38 PM
RED ALERT!: 2f3f8cca, don't worry, he is banned now.
Delta
05-28-2003, 11:22 PM
i was just wondering....if a user uses proxies... how would you ban him ?
or may be you should do something about it.
CrazyDT
05-29-2003, 01:12 AM
I think a slick way to do is to put some stinky cookie on that person's machine so that the server can detect/smell from miles away :D An average user wouldn't realize what's going on.
MegaZ
05-29-2003, 09:23 AM
Delta, well, if a banned user uses a proxy I'll start banning those proxies as well - there is no better way.
CrazyDT, I think if someone knows how to get around with a proxy will definitely find a way how to delete cookies :)
Delta
05-29-2003, 10:28 AM
Delta, well, if a banned user uses a proxy I'll start banning those proxies as well - there is no better way.
CrazyDT, I think if someone knows how to get around with a proxy will definitely find a way how to delete cookies :)
basically, you are saying you can't ban, since the number of proxies countless....one website may have over 400 proxy links :)
I would simply disable the proxy access, since you are not having presidential voting going on here.
-cheers
MegaZ
05-29-2003, 10:38 AM
Delta, you can't disable proxy access. There is simply no way. Most proxies don't even identify themselves as proxies.
MegaZ
http://forum.ru-board.com/topic.cgi?forum=21&bm=1&topic=2012#1
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