Prove the statement

[Einstein]

Can anyone prove 2*2=5

[varatar]

uzbeklar luboy natijani keltirib chiqarishadi, ozi 2*2 nechi bolishini holavosan?

[SUN6500]

2*2=4 Bu fact. Ammo O'zbekchiliy qivorin' degandan so'ng 1 ni pripiska qivoramiza. Natija 2*2+Ozbeychiliy(1)=5 )

[nobody]

Hi folks.
Einstein, your question makes sound, but some guys even dont have an idea about it.
Ok, lets prove it,i.e 2*2=5
As long as 2*2=4 i use 4 instead of 2*2.So we are going to prove 4=5

Firstly,As we know from simple ariphmetics :

(4-4)=(5-5)

Then we multiple 4 on left hand side of equality and 5 on right hand side.
Here we have following equation:

4*(4-4)=(5-5)*5

I think that everybody keeps with me, everybody understand that above equation gives us overall
0=0

Next step is, as we know again from this simple ariphmetics DIVIDING THE RIGHT AND LEFT HAND SIDES OF EQUATION TO EQUAL NUMBERS DOES NOT CHANGE THE OVERALL EQUATION .
Here we divide the left hand side of equation to (4-4) and the right hand side of equation to (5-5) . It doesnt change the overall equation, because as we told before
(4-4)=(5-5)

Allright, the new equation is

{4*(4-4)}/(4-4)={5*(5-5)}/(5-5)

So, i think everybody does understand what is the next step. The next step, again as we know from simple arithmetics equal numbers cancel each others when any number is divided to another. In this equation, on the left hand upper (4-4) cancels lower (4-4) and on the right hand side upper (5-5) cancels lower (5-5) or vice versa.

So, what do we have here? We have following equation ( i'd rather not to call it equation)

4=5

I hope you understand me Dear Einstein. If not i cant explain it any more clear than i did.
I proved it with the simple rules of mathematics . Clearly anyone can prove by this method anyone can equate any number to another. BUT , if you do know again the simple rules of mathematics i got wrong
somewhere, which is quite easy to catch up.
So, Dear Einstein,( or anyone else) try to identify where i wrongly used the mathematician rules.

Thank you for attention
nobody

[einstein22]

Nobody:

(4-4)=(5-5)=0, right?
But, if I remember correctly, you cannot divide by zero.

Regards,
einstein22

[IcyCool]

true, no division by zero... ;)

[nobody]

Ohho guys, nobody ni mot kildizlaku ;)

nobody

[IIIEP]

{4*(4-4)}/(4-4)={5*(5-5)}/(5-5)

meaning 0/0

1*0=0 1=0/0
2*0=0 2=0/0
3*0=0 3=0/0
... ...

so there is no meaning in 0/0
i guess

[Zanuda]

Umniye nashlis', zachem dokazivat' nevernoye? Uje vsyo do vas bilo dokazano.

Vo vseh etih "dokazatel'stvah" yest' hotya bi odna oshibka, kotoruyu nekotoriye chayniki umudryayutsya ne zametit'...

:)

[Guli]

Theorem: 4 = 5
Proof:
16 - 36 = 25 - 45
4^2 - 9*4 = 5^2 - 9*5
4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4
(4 - 9/2)^2 = (5 - 9/2)^2
4 - 9/2 = 5 - 9/2
4 = 5

source http://www.moonsighting.com/jokes.html

[Guli]

Einstein 22 :)?
Nichik?
chaqqonmi?

[varatar]

hmm, man Chukotkaga surdim.... :O

[nobody]

Hi everybody
Varatar hech era getmin dur, hali garak bolib kolasan.
Guli, your prove is correct , at least first 4 lines.
Ok, in 4th line we have (4 - 9/2)^2 = (5 - 9/2)^2 which is all right. But , when we take square root of left and right hand sides of equation we should take into account one rule, which is the square root of any number can not be negative number. So, right hand side is OK in this case as long as (5-9/2)=0.5>0 . But the left hand side can not be (4-9/2) as long as it is negative number, i.e
(4-9/2)=(4-4.5)=-0.5

Instead of this, one should use (9/2-4) which is positive number.
So, after all your equation in the 5th line should be
(9/2-4)=(5-9/2)
and the next step
0.5=0.5
which is nothing to do with 4=5 .

nobody22

[einstein22]

Guli: bravo... dim chaqqon :)

Nobody: mabodo 20chi maktabda o'qimaganmisan? :)

-einstein22

[Guli]

yoq 20da mas 41 da Toshkentda

san Na Hanqa?Urganch?Khiva?Shovot :)?


hosh asa

Umka

[varatar]

man Tashauz. :)
Chukotkada hozir nechi gradus sovuq ekan a?

[nobody]

Eistein22--> Ustinnan tushding! ;) (lakin choto sani donimin duribman) ???

Vratar, borma Chukotkaga, lutshe Antraktidaga bor. Pinguinlani gorib kaytasan(agar kaytib bilsang) :&

nobody

[Guli]

varatar davai luchse ko mne na graduation kak obeshal odam

Gorkiyda Tashauz mahallasi bormidi? :)?

[varatar]

qachon ozi graduation? choto mi v UK sobirayemsa ozimizcha.
hehe, Maksim Gorkiy sux, Tashauz rulez ! :) (potom skaju pochemu)

[Guli]

Yol bulsin
pereday privet manchester United ot Umki

ya naverno skoro domoi daje na graduation ne ostanus
problemi
zvoni ne propoday

[varatar]

hmmm, shas pozvonu.

[optimist]

DINAMO URGANCH ruleZZZZZZZZZZZZZZ!!!

[nobody]

OPTIMIST jora Dinamoni na alokasi bo Matematikaga???? O'zi 1-ligada yotibdiku, yena nera Ruiezzzz boladi akan? Aldin bir Oliy ligaga chestniy chikib olsin, keyin go'ramiz Rulezzz mi yo boshkami. Shuncha yil Futbol go'rib Bir hazzatmadim. (One exception, o'tgan yili Toshkentda Pahtakorni 3:2 ga utganda bir hazzatvadim).

nobody

[nobody]

All right Guys, i have one more Question( litlle question).
What is the Square Root of (-16) ?

nobody

[Guli]

pod kornem otrisatelniz znakov u sifr ne bivaet
if that is an answer to your question
varatar ti je u nas matematik podderji
square root of 16 would be 4 and -4 though
-16 in power 2 would be 256

[varatar]

hehe, last question was the same (Square root of -16) kogda GMAT zdaval, 17 minut dumal blin v konse, ohirida serevno guess sdelal. :)

[Tupoy]

Guys just to remind one thing before you 're gonna go further.

At that time Einstein was drunk
:)

[einstein22]

Ya znayu eto uzhe chereschur, no vsyo zhe:
sqrt(-16)=sqrt(-1*16)=4i

"Horazm" qachon 1chi ligaga tushib getdi???

-einstein22

[nobody]

Eistein Gap yok! ;-) ;-)

Horazm o'tgan yili ohirdan 3-orinnimiay yo 2-orinnimiay olib tushib getdi. Hozir 1-ligada yurgandi futbol oynaaab.

nobody.

[nobody]

pod kornem otrisatelniz znakov u sifr ne bivaet --- Bivaet Guli, bivaet. V jizni vse bivaet. Snachala nas uchili shto Nelza otnimat bolshoe chislu ot mensher, naprimer, 1-3 (odin minus tri) ne imeet znachenie. No ponatom nas pereuchili shto tak mojno, t.e. 1-3= -2 .
Snachala nas uchili shto nelzya Malenkuyu sifri delit na bolshuyu ili nechotnuyu k chotnomu, naprimer 2/4 ili 3/4 ne imeet ne kakogo znachenie. No potom nas esho pereuchili shto tak mojno,t.e 2/4=0.5 i 3/4=0.75
I snachala nas uchili shto pod kornem otritsatelnih sifr i znakov ne bivaet t.e. (-16) ne imeet nikakogo otveta. No potom okazalsa shto tak mojno. Znachit otvet(kak skazal Eistein)

The square root of (-16) is equal to 4i or 4*i where the square of i is equal to (-1)

nobody.

[nobody]

Vratar jora, endi korkmasdan GMAT topshitavar. ;)

[nobody]

Vratar, ohirgi sozni "topshiraver" deb oki.

[varatar]

hmm, choto manavi answerlarga qarab korilar:
square root of -16 ni x deb olish kere edi

A) x is an elemant of Z
B) x is an element of I
C) x is an element of K
D) all of them correct

[nobody]

Vratar , the right answer is B. Because, as i told u before, the square roots of all negative numbers are written as number*i(or I). So, If we assume (-16) to be x , then x is the element of I. Got it?

nobody.

[varatar]

hehe, do you know what I stands for?
it should be some number range like Z, but not an i.

This is very old topic, though, but still,

'I' stands for, 'imaginary number'

[Himik.]

imaginary, because sqrt of a negative number does not exist, so we have to imagine them. They have trivial application in real world problems.

[LunatiK]

Let me try to prove this statement.

Look at the attachment.

If the attachment doesn't appear:

Assume a, b are natural numbers and a > b . So there is such a c, (c is also a natural number) that
a = b + c. Multiply both side by (a – b).

a*(a – b) = (b + c)*(a – b)
a2 – ab = ab – b2 + ac – bc
a2 – ab – ac = ab – b2 – bc
a (a – b – c) = b (a – b – c)
a = b

As a > b , let’s assume a = 5 and b = 2, so 5 = 2. By the same way we can prove that 1 = 2. We know that if x = y and z = t ,
then x*z = y*t.

5 = 2
1 = 2
5*1 = 2*2
5 = 2*2

Sincerely Spy.

Let me try to prove this statement.

Look at the attachment.

If the attachment doesn't appear:

Assume a, b are natural numbers and a > b . So there is such a c, (c is also a natural number) that
a = b + c. Multiply both side by (a – b).

a*(a – b) = (b + c)*(a – b)
a2 – ab = ab – b2 + ac – bc
a2 – ab – ac = ab – b2 – bc
a (a – b – c) = b (a – b – c)
a = b

As a > b , let’s assume a = 5 and b = 2, so 5 = 2. By the same way we can prove that 1 = 2. We know that if x = y and z = t ,
then x*z = y*t.

5 = 2
1 = 2
5*1 = 2*2
5 = 2*2

Sincerely Spy.
.
(a-b-c)=0 you cannot devide 0/0
A simple mind perhaps would not notice it, but good try though

[Himik.]

Let me try to prove this statement.

Look at the attachment.

If the attachment doesn't appear:

Assume a, b are natural numbers and a > b . So there is such a c, (c is also a natural number) that
a = b + c. Multiply both side by (a – b).

a*(a – b) = (b + c)*(a – b)
a2 – ab = ab – b2 + ac – bc
a2 – ab – ac = ab – b2 – bc
a (a – b – c) = b (a – b – c)
a = b

As a > b , let’s assume a = 5 and b = 2, so 5 = 2. By the same way we can prove that 1 = 2. We know that if x = y and z = t ,
then x*z = y*t.

5 = 2
1 = 2
5*1 = 2*2
5 = 2*2

Sincerely Spy.
.
(a-b-c)=0 you cannot devide 0/0
A simple mind perhaps would not notice it, but good try though

there is no way, one could proove the statement 4=5, or 1+1=1 etc.

[LunatiK]

Well done

Varatar!!!

Bahti masmisan? nima qaytip kettingmi Uzb.ga.

Sani qolmoqchi dep eshitgan edim.
hmmmm????